日期判断

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/*
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功能：日期判断
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日期：2013-06-09
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*/
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#include<stdio.h>
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#include<stdlib.h>
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int isLeapYear(int iYear);
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int dayofWeek(int iYear,int iMonth,int iDay);
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int weekofYear(int iYear,int iMonth, int iDay);
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int main(void)
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{
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  int iYear,iMonth,iDay;
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  printf("请输入一个日期（“年-月-日”形式）：");
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  scanf("%d-%d-%d",&iYear,&iMonth,&iDay);
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  printf("%d年%d月%d日属于%d年的第%d个星期。n",iYear,iMonth,iDay,iYear,weekofYear(iYear,iMonth,iDay));
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  system("pause");
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  return 0;
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}
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//参数：int iYear 待判断的一个年份
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//返回：int 若iYear是闰年，则返回1，否则返回0；
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int isLeapYear(int iYear)
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{
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     if((iYear%4)&&(iYear%100)||(iYear%400))
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   {
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       return 1;
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   }
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   else
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   {
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      return 0;
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   }
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}
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//功能：判断一个日期是一周中的星期几
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//参数：int iYear 年份
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//      int iMonth 月份
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//      int iDay 日期
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//返回：int 返回当前日期是一周中的星期几
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int dayofWeek(int iYear,int iMonth,int iDay)
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{
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  int i,days=0,weekDay;
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  int days1[12]={31,28,31,30,31,30,31,31,30,31,30,31};
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  if(0==isLeapYear(iYear))
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  {
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      for(i=0;i<iMonth-1;i++)
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    {
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        days=+days1[i];
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    }
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       days+=iDay;
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  }
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  else
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  {
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     if (iMonth>2)
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     {
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        for(i=0;i<iMonth-1;i++)
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     {
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         days=+days1[i];
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     }
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        days+=iDay+1;
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     }
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     else
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     {
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      for(i=0;i<iMonth-1;i++)
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      {
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        days=+days1[i];
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      }
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      days+=iDay;
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     }
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  }
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  weekDay=((iYear-1)+(iYear-1)/4 -( iYear-1 /100 )+( iYear-1 / 400 ) + days) % 7;
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  switch (weekDay)
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  {     case 0: weekDay = 1;break;
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          case 1: weekDay = 2;break;
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        case 2: weekDay = 3;break;
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      case 3: weekDay = 4;break;
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      case 4: weekDay = 5;break;
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      case 5: weekDay = 6;break;
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      case 6: weekDay = 7;break;
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  }
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}
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//功能：判断一个日期是这一年中的第几个星期
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//参数：int iYear 年份
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//      int iMonth 月份
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//      int iDay 日期
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//返回：第几个星期
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int weekofYear(int iYear,int iMonth, int iDay)
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{
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  int weekOfYear,days=0,i;
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  int days1[12]={31,28,31,30,31,30,31,31,30,31,30,31};
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  if(0==isLeapYear(iYear))
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  {
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      for(i=0;i<iMonth-1;i++)
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    {
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        days=+days1[i];
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    }
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       days+=iDay;
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  }
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  else
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  {
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     if (iMonth>2)
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     {
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        for(i=0;i<iMonth-1;i++)
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     {
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         days=+days1[i];
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     }
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        days+=iDay+1;
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     }
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     else
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     {
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      for(i=0;i<iMonth-1;i++)
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      {
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        days=+days1[i];
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      }
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      days+=iDay;
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     }
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  }
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  weekOfYear= (int) ((days-dayofWeek(iYear,1,1)+6.3)/7)+1;
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}