“循环”左移

方法一（不利于程序扩展）： /* 功能：“循环”左移 日期：2013-04-01 */ #include<stdio.h> #include<stdlib.h> #include<math.h> int main(void) { int number1,number2,num1,num2,num3; printf(“请输入一个三位数：”); scanf(“%d”,&number1); num1 = number1 % 10; num1 = num1 % 10; num2 = number1 / 100; num3 = number1 % 100; num3 = num3 / 10; number2 = num1 * 100 + num2 * 10 + num3; printf(“循环左移2位后的整数是：%dn”,number2); system(“pause”); return 0; } ______________________________________________________________________________ 方法二： /* 功能：“循环”左移 日期：2013-04-01 */ #include<stdio.h> #include<stdlib.h> #include<math.h> int main(void) { //int number1,number2,num1,num2,num3; //printf(“请输入一个三位数：”); //scanf(“%d”,&number1); //num1 = number1 % 10; //num1 = num1 % 10; //num2 = number1 / 100; //num3 = number1 % 100; //num3 = num3 / 10; //number2 = num1 * 100 + num2 * 10 + num3; //printf(“循环左移2位后的整数是：%dn”,number2); 不利于程序扩展 int num,hight,result pintf(“请输入一个三位数：”); scanf(“%d”,&num); result = num; result = num/100 + num%100*10; result = result/100 + result%100*10; printf(“循环左移2位后的整数是：%dn”,result); system(“pause”); return 0; }